How do you write the first five terms of the sequence a_n=3n+1an=3n+1?

2 Answers
Jim G.
Aug 10, 2018

4,7,10,13,164,7,10,13,16

Explanation:

"to obtain the first 5 terms substitute "n=1,2,3,4,5"to obtain the first 5 terms substitute n=1,2,3,4,5
"into "a_ninto an

a_1=(3xx1)+1=3+1=4a1=(3×1)+1=3+1=4

a_2=(3xx2)+1=6+1=7a2=(3×2)+1=6+1=7

a_3=(3xx3)+1=9+1=10a3=(3×3)+1=9+1=10

a_4=(3xx4)+1=12+1=13a4=(3×4)+1=12+1=13

a_5=(3xx5)+1=15+1=16a5=(3×5)+1=15+1=16

maganbhai P.
Aug 10, 2018

The first five terms are :4,7,10,13,16.:4,7,10,13,16.

Explanation:

Here ,

a_n=3n+1an=3n+1

n=1=>a_1=3(1)+1=3+1=4n=1⇒a1=3(1)+1=3+1=4

n=2=>a_2=3(2)+1=6+1=7n=2⇒a2=3(2)+1=6+1=7

n=3=>a_3=3(3)+1=9+1=10n=3⇒a3=3(3)+1=9+1=10

n=4=>a_4=3(4)+1=12+1=13n=4⇒a4=3(4)+1=12+1=13

n=5=>a_5=3(5)+1=15+1=16n=5⇒a5=3(5)+1=15+1=16

Hence ,the first five terms are :4,7,10,13,16.:4,7,10,13,16.

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