How do you find the center and radius of the circle $2(x-3)²+2y²=8$ ?

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Answer 1 · 2018-08-12T02:48:46

Divide by $2$ both sides of the equation to get

$(x-3)^2+y^2=4$

or

$(x-3)^2+(y-0)^2=2^2$

Hence the center is the point $(3,0)$ and the radius is $r=2$

How do you find the center and radius of the circle 2(x-3)²+2y²=82(x-3)²+2y²=8?