Question

What is the vertex of `y=2 (x-3)^2+4`?

Answer 1

`"vertex "=(3,4)`

Explanation:

`"the equation of a parabola in "color(blue)"vertex form"` is.

`•color(white)(x)y=a(x-h)^2+k`

`"where "(h,k)" are the coordinates of the vertex and a"`
`"is a multiplier"`

`y=2(x-3)^2+4" is in this form"`

`"vertex "=(3,4)`

`"since "a>0" then minimum turning point "uuu`
graph{2(x-3)^2+4 [-10, 10, -5, 5]}