How do you solve the inequality $d + 6 ≤ 4d - 9$ or $3d -1 <2d + 4$ ?

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Answer 1 · 2018-08-12T11:59:00

$d+6 leq 4d-9$

Subtract $d$ from both sides

$6 leq 3d-9$

add 9 to both sides

$15 leq 3d$

Divide by 3

$5 leq d$

$3d-1 < 2d+4$

Subtract $2d$ from both sides

$d-1 < 4$

Add 1 to both sides

$d < 5$

How do you solve the inequality d + 6 ≤ 4d - 9d + 6 ≤ 4d - 9 or 3d -1 <2d + 43d -1 <2d + 4?