How do you write $log_2(x)=5$ in exponential form?

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Answer 1 · 2018-08-12T17:24:06

$x=2^5$

$"using the "color(blue)"law of logarithms"$

$•color(white)(x)log_b x=nhArrx=b^n$

$"here "b=2" and "n=5$

$log_2 x=5hArrx=2^5$

How do you write log_2(x)=5log_2(x)=5 in exponential form?