2/a-2/b / 1/a^2 - 2/b^2 this is a division problem dealing with fractions and variables ?

Question

2/a-2/b / 1/a^2 - 2/b^2 this is a division problem dealing with fractions and variables ?

1 Answer

Impact of this question

1161 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-23T07:09:51

$\frac{\frac{2}{a} - \frac{2}{b}}{\frac{1}{a^{2}} - \frac{2}{b^{2}}} = \frac{2 a b (b - a)}{b^{2} - 2 a^{2}}$ $(2/a-2/b)/(1/a^2-2/b^2)=(2ab(b-a))/(b^2-2a^2)$

Explanation:

$\frac{\frac{2}{a} - \frac{2}{b}}{\frac{1}{a^{2}} - \frac{2}{b^{2}}}$ $(2/a-2/b)/(1/a^2-2/b^2$

= $\frac{\frac{2 b - 2 a}{a b}}{\frac{b^{2} - 2 a^{2}}{a^{2} b^{2}}}$ $((2b-2a)/(ab))/((b^2-2a^2)/(a^2b^2))$

= $\frac{2 b - 2 a}{a b} \times \frac{a^{2} b^{2}}{b^{2} - 2 a^{2}}$ $(2b-2a)/(ab)xx(a^2b^2)/(b^2-2a^2)$

= $\frac{2 (b - a)}{a b} \times \frac{a b \times a b}{b^{2} - 2 a^{2}}$ $(2(b-a))/(ab)xx(abxxab)/(b^2-2a^2)$

= $(2(b-a))/cancel(ab)xx(cancel(ab)xxab)/(b^2-2a^2)$

= $(2ab(b-a))/(b^2-2a^2)$

Science

Math

Humanities

... and beyond

2/a-2/b / 1/a^2 - 2/b^2 this is a division problem dealing with fractions and variables ?

1 Answer

Explanation:

Related questions

Impact of this question