Question

5.00 L of a gas is collected at 22.0°C and 745.0 mmHg. When the temperature is changed to standard, what is the new pressure?

Answer 1

Use the Ideal Gas Laws to calculate the change. `(P_1 * V_1)/T_1 = (P_2 * V_2)/T_2`

Explanation:

STP is 0°C (273.15K)and 760mm Hg. The temperatures must be in K for the ratio to be correct.

`(P_1 * V_1)/T_1 = (P_2 * V_2)/T_2`

`(745 * 5.00)/295.15 = (760 * V_2)/273.15 ; V_2 = 273.15/760 * [(745 * 5.00)/295.15]`

`V_2 = 4.53L`