Question #dc381

1 Answer
Jan 14, 2014

42.88 % "C" by mass and 57.12 % "O" by mass

Explanation:

Percentage composition is the percentage by mass of each element in a compound.

"% by mass" = "mass of element"/"total mass of all elements" × 100%

To find the % composition of "CO", you calculate the % by mass of each element in a given mass of "CO". It is simplest to use 1 mol of "CO".

1 mol "CO" contains 1 mol of "C" and 1 mol of "O".

28.01 g "CO" contain 12.01 g "C" and 16.00 g "O".

"% C by mass" = "mass of C"/"mass of CO" × 100 % = (12.01 color(red)(cancel(color(black)("g"))))/(28.01 color(red)(cancel(color(black)("g")))) × 100 % = 42.88 %

"% O by mass" = "mass of O"/"mass of CO" × 100 % = (16.00 color(red)(cancel(color(black)("g"))))/(28.01 color(red)(cancel(color(black)("g")))) × 100 % = 57.12 %