Question #e35ee

1 Answer
Apr 23, 2014

The moment of inertia is calculated from the sum

I=m_1timesr_1^2 + m_2timesr_2^2 + m_3timesr_3^2I=m1×r21+m2×r22+m3×r23

where r_iri is the distance of point mass ii from the center of mass of the three points. The square of each distance is calculated in Cartesian coordinates as

r_i^2=(x_i-x_(cm))^2+(y_i-y_(cm))^2r2i=(xixcm)2+(yiycm)2

The center-of-mass coordinates (x_(cm),y_(cm))xcm,ycm) can be found from the simple formula below if you know the masses of the three points and their coordinates in any (x,y) plane.

x_(cm) = (m_1 timesx_1 + m_2 times x_2 + m_3 times x_3)/(m_1+m_2+m_3xcm=m1×x1+m2×x2+m3×x3m1+m2+m3

y_(cm) = (m_1 timesy_1 + m_2 times y_2 + m_3 times y_3)/(m_1+m_2+m_3ycm=m1×y1+m2×y2+m3×y3m1+m2+m3