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Answer 1 · 2014-09-11T13:32:31

If its 1.4% by mass, then that means there are $0.014 \cdot 200.0 = 2.8 m g$ $0.014*200.0=2.8mg$ of the 214 isotope.

$2.8 m g = 0.0028 g$ $2.8 mg=0.0028 g$

$\frac{0.0028}{214} = 1.31 \cdot 10^{- 5} m o l$ $0.0028/214=1.31*10^(-5) mol$
$2.8$ $2.8$ mg of lead-214 is therefore $1.31 \cdot 10^{- 5}$ $1.31*10^(-5)$ mol

$1.31 \cdot 10^{- 5} \cdot 6.02 \cdot 10^{23} = 7.9 \cdot 10^{18}$ $1.31*10^(-5)*6.02*10^(23)=7.9*10^18$ atoms
$1.31 \cdot 10^{- 5}$ $1.31*10^(-5)$ mol of a substance therefore contains $7.9 \cdot 10^{18}$ $7.9*10^18$ atoms.

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