Question #c450e

1 Answer
Sep 25, 2014

The equilibrium constant is 3×102.

Explanation:

First, write the balanced chemical equation with an ICE table.

mmmmmmmmmmFe3+m+mSCN-mmFeSCN2+
I/mol⋅L-1:mmm1.0×10-3mm8.0×10-4mmmm0
C/mol⋅L-1:mmmml-xmmmmmll-xmmmmmll+x
E/mol⋅L-1:l1.0×10-3xm8.0×10-4xmmmx

At equilibrium, [FeSCN2+]=1.7×10-4lmol/L=xlmol/L

So x=1.7×10-4

Then

[Fe3+]=(1.0×10-3x)lmol/L=(1.0×10-31.7×10-4)lmol/L

=8.3×10-4lmol/L (1 significant figure + 1 guard digit)

and

[SCN-]=(8.0×10-4x)lmol/L=(8.0×10-41.7×10-4)lmol/L

=6.3×10-4lmol/L

Kc=[FeSCN2+][Fe3+][SCN-]=1.7×10-48.3×104 ×6.3×104=3×102

Note: The answer can have only 1 significant figure, because the initial concentration of Fe3+ has only one digit after the decimal point. If you need more precision, you will have to recalculate.