Question

Question #c3e63

Answer 1

The empirical formula is `C_3F_6O_2`

Write down the ratio by mass C : F :O in grams:

163.8 : 518.1 : 145.4

Now work out the ratio by moles by dividing by the mass of 1 mole of each element. This is the `A_r` value in grams.

`A_r[C]=12` `A_r[F]=19` `A_r[O] = 16`

Ratio moles:

`163.8/12` : `518.1/19` :`145.4/16`

`rArr` 13.65 : 27.27 : 9.1

Divide through by 9.1 gives:

1.5 : 3 : 1

So x by 2 gives:

3 : 6 : 2

So the empirical formula is:

`C_3F_6O_2`