Boyle's law states that the pressure and the volume of a gas are proportional to one another, if temperature and the number of moles are kept constant.
Starting from the ideal gas law, PV = nRT, and taking into account the premise that moles and temperature are kept constant, we get
V = 1/P * nRT -> V = 1/P * k, where
k = nRT = const ant
Now, a plot of V vs 1/P will look like this (the graph on the right)
)
Notice that the line starts from the origin, which is consistent with the premise that b=0 -> from y = mx +b
SInce your linear equation is given,
y= 2060.1x + 2*10^(-5), we can assume that 2*10^(-5) is negligible; all you need now is a second point on the line in order to express the slope. The most obvious point on this graph is (0,0), which will give
m = (y_1 - y_2)/(x_1 - x_2) = (3.1146 - 0)/(0.001526618 - 0) = 2040.2, which represents the slope of the graph V vs 1/P, and the constant k = nRT.
