Question #3177e

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Answer 1 · 2014-11-22T19:07:20

The line perpendicular to $3 x + 9 y = 0$ $3x+9y=0$ has the equation $y = 3 x$ $y=3x$

$3 x + 9 y = 0$ $3x+9y=0$

Putting this into the form $y = m x + c$ $y=mx+c$ we get:

$y = \frac{- x}{3}$ $y=(-x)/(3)$

So $m = - \frac{1}{3}$ $m=-(1)/(3)$

If two lines A and B are perpendicular then gradient of

B = -1/gradient of A

So gradient of B $\frac{- 1}{- \frac{1}{3}} = 3$ $(-1)/(-(1)/(3)) =3$

So the perpendicular line has the equation $y = 3 x$ $y=3x$

Should really be under Algebra but there you go.