Question

Question #f78a9

Answer 1

When you have a quadratic function `y=ax^2+bx+c` to find the `x` intercepts you must set the value of `y` equal to zero (a point on the `x` axis, the intercept, must have coordinate `y` equal to zero otherwise it doesn't lie on the `x` axis).
But, when `y=0` in your function you are left with: `ax^2+bx+c=0` which is a quadratic equation.
If you solve this equation you'll find (possibly) two values of `x_1 and x_2`.
Your x-intercepts will then be the points of coordinates:
`(x_1,0)`
`(x_2,0)`

Consider the following example:

Important:
It is possible that your second degree equation might not have solutions or have one solution only, depending upon the value of `Delta=b^2-4ac` of your particular equation.