Question

Question #3fdac

Answer 1

The key is to use powers to express your two terms.

Your first term can be written as `8 = 2^3`, and your second term can be written as `z^6 = (z^2)^3`, which makes your expression

`2^3 + (z^2)^3 = (2 + z^2)(2^2 -2*z^2 + (z^2)^2)`

`2^3 + (z^2)^3 = (2 + z^2)(4 - 2z^2 + z^4)`

I've used the fact that

`a^3 + b^3 = (a+b)(a^2 - ab + b^2)`