How many atoms of vanadium are present in 185 mg of this element?

1 Answer
Stefan V.
Jan 26, 2015

The answer is 2.19⋅1021 atoms of vanadium are in 185 mg.

Since you know what the mass of 1 atom is, and you know the number of grams for which you must determine the number of atoms, this boils down to setting up a simple conversion factor:

185 mg⋅1 gram1000 mg⋅1 atom8.46⋅10−23g=2.19⋅1021atoms

You could double check your answer by comparing the number of atoms in 185 mg to the number of atoms in 1 mole of vanadium, or 50.9 g.

185 mg represents a mass about 300, or 3⋅102, times smaller than 50.9 g, so that's how many times less atoms you'll have compared to the number of atoms in 1 mole, 6.022⋅1023.

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