What is the molarity if $"11 g CaCl"_2"$ are dissolved in one liter of solution?

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Answer 1 · 2015-03-16T20:35:28

The molarity of CaCl₂ is 0.99 mol/L.

To get the molarity, you divide the moles of solute by the litres of solution.

$"Molarity" = "moles of solute"/"litres of solution"$

$"Moles of CaCl₂" = 11 cancel("g CaCl₂") ×"1 mol CaCl₂"/(110.98 cancel("g CaCl₂")) = "0.099 mol CaCl₂"$ .

$"Litres" = "100 mL" = "0.100 L"$

$"Molarity" = "moles of solute"/"litres of solution" = "0.099 mol"/"0.100 L" = "0.99 mol/L"$

What is the molarity if "11 g CaCl"_2""11 g CaCl"_2" are dissolved in one liter of solution?