The initial velocity for the reaction will be "350 nmol s"^(-1).
Start from the Michaelis-Menten equation
V_0 = (V_"max" * [S])/(V_"max" + [S])
When an uncompetitive inhibitor is introduced, the equation takes this form
V_0 = (V_"max" * [S])/(K_m + [S] * underbrace((1 + ([I])/K_I))_(alpha)
But (1 + ([I])/K_I) is actually equal to alpha, the degree of inhibition, which implies that the equation becomes
V_0 = (V_"max" * [S])/(K_m + [S] * alpha)
Now plug your values and solve for V_0
V_0 = ("950 nmol s"^(-1) * 350cancel(mu"mol L"^(-1)))/((175+ 350 * 2.20)cancel(mu"mol L"^(-1))
V_0 = 350/(945) * "950 nmol s"^(-1) = "351.85 nmol s"^(-1)
Rounded to two sig figs, the number of sig figs given for V_"max" and [S], the answer will be
V_0 = color(green)("350 nmol s"^(-1))
