Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

Question #05d9c

1 Answer

Michael · Ernest Z. · Stefan V.

Apr 14, 2015

There are 0.75 moles.

$A_{r}$ $A_r$ of phosphorus = 30.97. This means that 1 mole of phosphorus atoms weighs 30.97g

So 1 mole of $P_{4}$ $P_4$ molecules weighs $4 \times 30.97 = 123.88 g$ $4xx30.97= 123.88"g"$

The number of moles $n$ $n$ = mass/mass of 1 mole:

$n = \frac{m}{M_{r}} = \frac{92.91}{123.88} = 0.75$ $n=m/M_r=92.91/123.88=0.75$

Related questions

See all questions in The Mole

Impact of this question

2243 views around the world

You can reuse this answer
Creative Commons License