Question #b6669

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Answer 1 · 2015-04-30T01:07:32

The new volume of hydrogen gas at STP is $4550 "L"$ .

The equation for the combined gas law is $(P_1V_1)/T_1=(P_2V_2)/T_2$ .

If I read your problem correctly, you want the volume of hydrogen gas after it has been adjusted to STP.

Known:
$P_1=100.0 "atm"$
$V_1=50.0 "amt"$
$T_1=27.0^"o""C+273.15=300.2K"$

$P_2=1.00 "atm"$
$T_2=0^"o""C+273.15=273.15K"$

Unknown:
$V_2$

Solution: Rearrange the equation to isolate and solve for $V_2$ .

$V_2=(P_1V_1T_2)/(T_1P_2)=(100.0cancel"atm" * 50.0 "L" * 273.15cancel"K")/(300.2cancel"K" * 1.00cancel"atm")=4550 "L"$