How do you simplify $\sqrt{\frac{9}{8}} \cdot \sqrt{\frac{7}{6}}$ $sqrt(9/8)*sqrt(7/6)$ ?

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Answer 1 · 2015-04-30T04:34:27

Simplify $\sqrt{\frac{9}{8}} \cdot \sqrt{\frac{7}{16}}$ $sqrt(9/8) * sqrt(7/16)$ .

$\frac{\sqrt{9}}{\sqrt{8}} \cdot \frac{\sqrt{7}}{\sqrt{16}}$ $sqrt 9/sqrt8 * sqrt7/sqrt16$ =

$\frac{3}{\sqrt{2} \sqrt{4}} \cdot \frac{\sqrt{7}}{4}$ $3/(sqrt2sqrt4) * sqrt7/4$ =

$\frac{3}{2 \sqrt{2}} \cdot \frac{\sqrt{7}}{4}$ $3/(2sqrt 2) * sqrt 7/4$ =

$\frac{3 \sqrt{7}}{8 \sqrt{2}}$ $(3sqrt 7)/(8sqrt 2)$ =

Rationalize the denominator.

$\frac{3 \sqrt{7}}{8 \sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}}$ $(3sqrt 7)/(8sqrt 2) * (sqrt 2)/(sqrt 2)$ =

$\frac{3 \sqrt{14}}{8 \sqrt{4}}$ $(3sqrt 14)/(8sqrt 4)$ =

$\frac{3 \sqrt{14}}{8 \cdot 2}$ $(3sqrt 14)/(8*2)$ =

$\frac{3 \sqrt{14}}{16}$ $(3sqrt 14)/16$

How do you simplify √98⋅√76sqrt(9/8)*sqrt(7/6)?