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Answer 1 · 2015-08-10T20:29:15

b. $K_"eq" = (["C"]^c)/(["B"]^b)$

For a general equilibrium reaction

$a"A" +b"B" ⇌ c"C" +d"D"$ ,

the equilibrium constant expression is

$K_"eq" = (["C"]^c["D"]^d)/(["A"]^a["B"]^b)$ .

However, solids are omitted from the expression.

If $"A"$ and $"D"$ are solids, the expression becomes

$K_"eq" = (["C"]^c)/(["B"]^b)$