Question #03339

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Answer 1 · 2016-01-03T04:19:46

a) Molality and d) mole fraction are not affected by temperature.

a) Molality

$Molality = \frac{moles of solute}{kilograms of solute}$ $"Molality" = "moles of solute"/"kilograms of solute"$

Both moles and kilograms are measures of mass, and mass does not change with temperature.

∴ Molality is not affected by temperature.

$Molarity = \frac{moles of solute}{litres of solution}$ $"Molarity" = "moles of solute"/"litres of solution"$

The volume of a liquid changes with temperature, so molarity is affected by temperature.

c) Normality

$Normality = \frac{equivalents of solute}{litres of solution}$ $"Normality" = "equivalents of solute"/"litres of solution"$

Normality depends on the volume of solution, so normality is affected by temperature.

d) Mole fraction

$Mole fraction=moles of componenttotal moles$ $"Mole fraction" = "moles of component"/"total moles"$

Moles do not change with temperature, so mole fraction is not affected by temperature.