Question #0989a

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Question #0989a

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Answer 1 · 2015-10-10T22:42:27

44m

Explanation:

Here are our equations
$y_{1} = y_{0} + v_{0} t + \frac{1}{2} a t^{2}$ $y_1=y_0+v_0t+1/2at^2$

When Y(of bag) is 0 the Y(of blimp) is 50
Also the $y_{0}$ $y_0$ for both is equal

$0 = y_{0} + 0 t + \frac{1}{2} \cdot (- 9.8) t^{2}$ $0=y_0+0t+1/2*(-9.8)t^2$
and we sub "t" with
$50 = y_{0} + 2 t + \frac{1}{2} \cdot 0 \cdot t^{2}$ $50=y_0+2t+1/2*0*t^2$ Is also $t = \frac{- y_{0} + 50}{2}$ $t=(-y_0+50)/2$

we get

$y_{0} = - (\frac{1}{2}) (- 9.8) {(\frac{- y_{0} + 50}{2})}^{2}$ $y_0=-(1/2)(-9.8)((-y_0+50)/2)^2$

$y_{0} = 44$ $y_0=44$

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Question #0989a

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