Is K_c dependent on initial concentrations?

1 Answer
Dec 12, 2015

K_C is not dependent on initial concentrations because that's not how it is defined. It is only for equilibrium concentrations.

The constant for initial concentrations (or "current" concentrations) is reserved for the Reaction Quotient Q, the not-yet-equilibrium constant. It is defined precisely the same way as K_C; just replace Q with K_C and note that the concentrations are the initial concentrations at the time.

Suppose we have this general reaction:

color(green)(2)A + B rightleftharpoons color(green)(3)C + color(green)(2)D

It is always defined like this for this reaction:

Q = (prod_j [P_j]_0^color(green)(nu_(P_j)))/(prod_i [R_i]_0^color(green)(nu_(R_i)))

K_C = (prod_j [P_j]_"eq"^color(green)(nu_(P_j)))/(prod_i [R_i]_"eq"^color(green)(nu_(R_i)))

where the prod symbol just means multiply the numbers that come after it, square brackets denote concentration (or if you know what activities are, use activities; no, I don't mean the activity series), 0 means "initial", R_i is each reactant of index i, P_j is each product of index j, and nu is the stoichiometric coefficient.

So, you can write this as:

Q = ([C]_0^color(green)(3)[D]_0^color(green)(2))/([A]_0^color(green)(2)[B]_0)

K_C = ([C]_"eq"^color(green)(3)[D]_"eq"^color(green)(2))/([A]_"eq"^color(green)(2)[B]_"eq")