Given that DeltaH_"combustion"^@ for "propane" is -2043*kJ*mol^-1, what mass of propane is required to give 425*kJ?
1 Answer
Nov 9, 2015
You have the equation; treat the energy as a product!
Explanation:
Normally, we would write the energy given as a negative quantity. Here, I have it listed as a reaction product (as indeed it is). Combustion of 1 mol propane gives 2043 kJ of energy. (That is 2043 kJ of energy are evolved per mole of reaction as written!)
So if 425 kJ of energy are evolved, then