Question

Question #eae13

Answer 1

The pressure will increase to `"5.63 atm"`.

Explanation:

Use Gay-Lussac's law, which states that when the volume of a gas is kept constant, its volume and pressure are directly proportional. The equation for this gas law is `P_1/T_1=P_2/T_2`.

`P_1="5.00 atm"`
`T_1="5.00"^"o""C"+273.15="278.15 K"`
`P_2=???`
`T_="40.0"^"o""C"+273.15="313.15 K"`

Solution
Rearrange the equation to isolate `P_2` and solve.

`P_2=(P_1T_2)/T_1`

`P_2=((5.00"atm") * (313.15"K"))/(278.15"K")="5.63 atm"`

You can learn more about the gas laws at http://chemistry.bd.psu.edu/jircitano/gases.html