Question #52ade

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Answer 1 · 2015-11-26T00:46:36

The final volume of nitrogen gas will be $"528 mL"$ .

Use the combined gas law with the equation $(P_1V_1)/(T_1)=(P_2V_2)/(T_2)$ .

Given/Known
$P_1="740 torr"$
$V_1="500. mL"$
$T_1="25"^"o""C"+273.15="298 K"$
$P_2="760 torr"$
$T_2="50"^"o""C"+273.15="323 K"$

Unknown
$V_2$

Equation
$(P_1V_1)/(T_1)=(P_2V_2)/(T_2)$

Solution
Rearrange the equation to isolate $V_2$ and solve.

$V_2=(P_1V_1T_2)/(T_1P_2)$

$V_2=(740cancel"torr"xx500. "mL"xx323cancel"K")/(298cancel"K"xx760cancel"torr")="528 mL N"_2"$