Question #b62d7

1 Answer
Dec 2, 2015

Delta G = -817kJΔG=817kJ

Explanation:

To solve this question we will use Hess's Law:

We need to rearrange the individual steps in order for the sum to give the desired equation:
CH_4(g) + 2O_2(g) → CO_2(g) + 2H_2O(l)CH4(g)+2O2(g)CO2(g)+2H2O(l)

For that we will do the following:
Step 1:
Since CH_4CH4 is needed to be in the reactant side, we will flip the reaction and in this case, we reverse the sign of DeltaGΔG:
CH_4(g)->2H_2(g) + C(s)" " " "-Delta G = 51 kJCH4(g)2H2(g)+C(s) ΔG=51kJ

Step 2:
2H_2(g) + O_2(g) → 2H_2O(l) " " " "Delta G = -474 kJ2H2(g)+O2(g)2H2O(l) ΔG=474kJ
This equation will be left the way it is.

Step 3:
C(s) + O_2(g) → CO_2(g)" " " "Delta G = -394kJC(s)+O2(g)CO2(g) ΔG=394kJ
This equation will be left the way it is.

Now we sum these three steps:
CH_4(g)->cancel(2H_2(g)) + cancel(C(s))" " " "-Delta G = 51 kJCH4(g)2H2(g)+C(s) ΔG=51kJ
cancel(2H_2(g)) + O_2(g) → 2H_2O(l) " " " "Delta G = -474 kJ2H2(g)+O2(g)2H2O(l) ΔG=474kJ
cancel(C(s)) + O_2(g) → CO_2(g)" " " "Delta G = -394kJC(s)+O2(g)CO2(g) ΔG=394kJ
-------------------
CH_4(g) + 2O_2(g) → CO_2(g) + 2H_2O(l)" " " "Delta G = -817kJCH4(g)+2O2(g)CO2(g)+2H2O(l) ΔG=817kJ

Here is a video about Hess's Law:
**Thermochemistry | Hess's Law, Enthalpy and Heating/Cooling Curve. **