Question #9c03e

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Answer 1 · 2016-06-23T07:57:20

9.72atm

Given

$V_1 ->"Initial volume of air"=400cm^3$

$P_1 ->"Initial pressure air"= 1atm$

$T_1 ->"Initial temperature air"= 15+273=288K$

$V_2 ->"Final compressed volume of air"=50cm^3$

$T_2 ->"Final temperature air"= 77+273=350K$

$P_2 ->"Initial pressure air"=?$

Now we have combined Boyle's and Charle's law relation as

$(P_2V_2)/T_2=(P_1V_1)/T_1$

$=>(P_2*50)/350=(1*400)/288$

$P_2=(8*350)/288=9.72atm$