Question #9c63a

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Question #9c63a

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Answer 1 · 2015-12-15T21:13:07

$0, 571 M$ $0,571M$

Explanation:

Since concentration is moles per unit volume $(c = \frac{n}{V})$ $(c=n/V)$ , and moles is mass over molar mass $(n = \frac{m}{M_{r}})$ $(n=m/(M_r))$ , we may find the molar concentration (molarity) as follows :

$c = \frac{n}{V} = \frac{6 m o l}{10, 5 d m^{3}} = 0, 571 m o l / d m^{3}$ $c=n/V=(6mol)/(10,5dm^3)=0,571 mol//dm^3$

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