How many copper atoms in a mass of $0.595*g$ of copper?

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Answer 1 · 2016-01-21T07:33:00

Avogadro's number of copper atoms has a MASS of $63.55$ $g$ . If you didn't know that, then where would we find it?

If we write $N_A$ $=$ $6.022xx10^(23)$ $mol^-1$ . Then we can estimate the number of copper atoms based on the MASS of the copper atoms.

So we need the proportion of $1$ $"mole"$ that $0.595$ $g$ represents.

$(0.595*g)/(63.55*g*mol^-1)$ $=$ $??$ $mol$ .

You then multiply this number by $N_A$ to get the NUMBER of copper atoms.

How many copper atoms in a mass of 0.595*g0.595*g of copper?