Question #e7bac

Question

6441 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-01T19:34:05

The electron configuration of $N$ $"N"$ is $[He] l 2 s^{2} 2 p^{3}$ $"[He]"color(white)(l) 2s^2 2p^3$ .

Nitrogen, $N$ $"N"$ , is located in Group 15, Row 2 of the Periodic Table.

It has atomic number $7$ $7$ .

This tells you that a neutral nitrogen atom has a total of $7$ $7$ electrons.

If you add electrons according to the Aufbau Principle, you get the electron configuration

$N: 1 s^{2} l 2 s^{2} 2 p^{3}$ $"N: " 1s^2color(white)(l) 2s^2 2p^3$

If you use the noble gas shorthand notation, you will get from

$"N: " overbrace(1s^2)^(["He"]) 2s^2 2p^3$

to

$"N: " ["He"]color(white)(l) 2s^2 2p^3$