Question #a877a

1 Answer
Feb 9, 2018

y inRR,y!=0

Explanation:

f(x)=1/(x^2+x-12)" expanding factors in denominator"

"divide terms on numerator/denominator by the highest"
"power of x that is "x^2

f(x)=(1/x^2)/(x^2/x^2+x/x^2-12/x^2)=(1/x^2)/(1+1/x-12/x^2)

"as "xto+-oo,f(x)to0/(1+0-0)

rArry=0larrcolor(red)"is an excluded value"

"range is "y inRR,y!=0

(-oo,0)uu(0,+oo)larrcolor(blue)"in interval notation"
graph{1/(x^2+x-12) [-10, 10, -5, 5]}