Find the definite integral $int_0^1dx/(2x-3)$ ?

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Answer 1 · 2016-10-12T15:09:50

$int_0^1dx/(2x-3)=-0.5493$

Let $u=2x-3$ , hence $du=2dx$ and

$intdx/(2x-3)=1/2int(du)/u=1/2lnu=1/2ln|2x-3|$

Hence, $int_0^1dx/(2x-3)$

= $1/2ln|2x-3|_0^1$

= $1/2ln|-1|-1/2ln|-3|$

= $1/2ln1-1/2ln3$

= $0-0.5493$

= $-0.5493$

Find the definite integral int_0^1dx/(2x-3)int_0^1dx/(2x-3)?