Question #fb855

1 Answer
Mar 15, 2016

0.20 M0.20M

Explanation:

  1. The equation is
    CaCO_3->CaO + CO_2CaCO3CaO+CO2
  2. Find the formula masses of CO_2CO2 and CaCO_3CaCO3
    CaCO_3CaCO3=100100 grams per mole
    Ca=1 Ca=1x 40=4040=40
    C=1 C=1x 12=1212=12
    O=3 O=3x 16=4816=48
    CO_2CO2=4444 grams per mole
    C=1 C=1x 12=1212=12
    O=2 O=2x 16=3216=32
  3. Find the mass of pure marble;
    mass pure=(actual mass)(purity)masspure=(actualmass)(purity)
    mass pure=((10g)(0.50)masspure=((10g)(0.50)
    mass pure=5 gmasspure=5g
  4. Convert mass CaCO_3CaCO3 to mole CaCO_3CaCO3
    5 cancel(g CaCO_3) x (1 mol CaCO_3)/(100 cancel(g CaCO_3)
    0.05 mol CaCO_3
  5. Find the mol CO_2; referring to the equation it's observed that both compounds have same number of mole; thus
    CO_2=0.05 mol
  6. Convert 250 ml to Li; 0.25 Li
  7. Therefore, to find the Molarity(M) use the formula:
    M=(n. mol)/(Li solution)
    M=(0.05 mol)/(0.25 Li)
  8. M=0.20 (mol)/(Li) or 0.20M