What volume at "SLC" is occupied by an 88*g mass of carbon dioxide?

A. 49*L;
B. 24.5*L;
C. 98*L;
D. "Cannot be determined."

1 Answer
Apr 2, 2016

Option A, 49 L.

Explanation:

Now you have (88.0*g)/(44.0*g*mol^-1) = 2*mol CO_2(g).

For this molar quantity of course we could solve the Ideal Gas equation, but, we know that 1 mol of Ideal Gas has a volume of 24.5 L under standard conditions of 298 K and 1 atm. I think that this is even given as supplementary information in the A level exams. Since we have 2 mol, there will be twice this molar volume.

The actual experimental volume will be very close to this value, as we have a regime of moderate pressures, and reasonably high temperatures.