Question #79b63

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Answer 1 · 2016-07-07T15:18:37

1st term=3
2nd term =12
3rd term =48

Let
#" the 1st term of GP "=a #
#" and common ratio "=r#

#" So 2nd term"= ar " and 3rd term"=ar^2#

By the 1st condition

#(ar^2)/a=16=>r=sqrt16=4#

By the 2nd condition

#ar^2-a=45=>a(4^2-1)=45=>a=3#

Hence

#"1st term "=3#

#"2nd term "=12#

#"3rd term "= 48#