Question #3f817

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Question #3f817

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Answer 1 · 2016-04-04T14:37:33

$6$ $6$ times that of the Moon's

Explanation:

Acceleration due to gravity on any astronomical body is:

$g_{b o d y} = G \frac{M_{b o d y}}{r_{b o d y}^{2}}$ $g_(body)=GM_(body)/r_(body)^2$

$g_{E a r t h} = G \frac{M_{E a r t h}}{r_{E a r t h}^{2}}$ $g_(Earth)=GM_(Earth)/r_(Earth)^2$

$g_{M o o n} = G \frac{M_{M o o n}}{r_{M o o n}^{2}}$ $g_(Mo on)=GM_(Mo on)/r_(Mo on)^2$

You can Google/Bing/Yahoo for the masses and the radii of the Earth and the Moon and find the ratio $\frac{g_{E a r t h}}{g_{M o o n}}$ $g_(Earth)/g_(Mo on)$ . It should be around $6$ $6$ .

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Question #3f817

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