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If $pH=12.5$ , what is $[H^+]$ ?

1 Answer

Apr 16, 2016

By definition, $pH$ $=$ $-log_10[H_3O^+]$ , equivalently, $-log_10[H^+]$ .

Explanation:

Thus, $[H^+]$ $=$ $10^(-12.5)$ $mol*L^-1$ $=??$

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