If a mass of "16.26 mg" contains 1.66 xx 10^20 atoms, what is the molar mass of that atom? If you have "1 million" silver atoms constituting a total of 1.79 xx 10^(-16) "g", what is the molar mass? "1 amu" = 1.660599 xx 10^(-24) "g".
1 Answer
Both questions ask the same thing in opposite ways.
One gives you
("16.26" cancel"mg")/(1.66xx10^20 cancel"atoms") xx "1 g"/("1000" cancel"mg") xx (6.0221413xx10^23 cancel"atoms")/"mol"
= color(blue)("58.988 g/mol") ,
which is close enough to cobalt, whose accepted value is
The other gives you
(1.79xx10^(-16) "g")/(10^6 cancel"Ag atoms")xx(6.0221413xx10^23 cancel"atoms")/"mol"
= color(green)("107.796 g/mol")
which is close enough to the accepted value of
In either case you still get
WHAT IS AMU?
You are not required to use the conversion
"1 g"/(6.0221413xx10^(23) "atoms") = "1 amu"
= 1.660599xx10^(-24) "g",
unless you want to. It just depends on whether you are talking about
CONVERTING BETWEEN G/MOL and AMU
You can still interconvert between
(58.988 cancel"g")/cancel"mol"xxcancel"1 mol"/(6.0221413xx10^23 cancel"atoms") xx "1 amu"/(1.660599xx10^(-24) cancel"g")xxcancel("1 atom")
~~ color(blue)(58.988) color(blue)("amu for one atom")
i.e. The experimental atomic mass of
So,