A gas enclosed in a piston that has a volume of 245*mL at 0 ""^@C, will express what volume at 95 ""^@C?

1 Answer
anor277
Apr 18, 2016

At constant pressure, V_1/T_1=V_2/T_2

Explanation:

The above was simply a restatement of Charles' Law.

Given your problem, and converting the temperatures to absolute values:

V_2=T_2xxV_1/T_1 = (273+95)*Kxx(245*mL)/((273+18)*K) ~=300*mL

Note that for these problems I am obliged to turn temperatures into absolute temperatures (why? because the Gas Laws assume absolute temperatures). I am NOT obliged to use standard volumes if I am consistent - I could have used pints and gills if I knew what they meant! Thus a measurement in millilitres is quite acceptable.

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