Question

Question #6f85b

Answer 1

`m=1.65g` of Neon in each tube.

Explanation:

We can modify the ideal gas law: `PV=nRT`, by using the expression of number of mole as:

`n=m/(MM)` where, `m` is the given mass and `MM=20.2g/(mol)` is the molar mass of neon.

Thus, `PV=m/(MM)RT=>m=(PVMM)/(RT)`

We will need first to convert `157kPa` to `atm`:

`?atm=157cancel(kPa)xx(1atm)/(101.325cancel(kPa))=1.55atm`

`=>m=(1.55cancel(atm)xx1.3cancel(L)xx20.2(g)/(cancel(mol)))/(0.0821(cancel(L)*cancel(atm))/(cancel(K)*cancel(mol))xx301cancel(K))=1.65g`