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Question #ea371

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Aug 2, 2017

$15.05$ $15.05$ x $10^{23}$ $10^23$

Explanation:

No.of moles of Sulfur dioxide $= 1.25$ $= 1.25$

Formula of sulfur dioxide $= S O_{2}$ $= SO_2$

No.of Oxygen atoms present in 1 molecule of $S O_{2} = 2$ $SO_2 =2$

Moles of Oxygen atoms present in $S O_{2}$ $SO_2$ = $2 \times 1.25$ $2 xx 1.25$ $\Rightarrow$ $=>$ $2.5$ $2.5$

No.of oxygen atoms $=$ $=$ Moles $\cdot$ $*$ Avogadro's number

$= 2.5 \times 6.022 \times 10^{23}$ $= 2.5 xx 6.022 xx 10^23$
$= 15.05 \times 10^{23}$ $= 15.05 xx10^23$

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