Question #04486

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Question #04486

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Answer 1 · 2016-05-19T13:02:25

Rounded to nearest foot $\to 314 {feet}^{2}$ $->314 " feet"^2$

Explanation:

Let the radius be $r$ $r$
Let the diameter be $d$ $d$
Let area be $a$ $a$

Known:
$a = π r^{2}$ $a=pir^2$

Same equation in a different form

$r = \frac{d}{2} \Rightarrow π r^{2} \to π {(\frac{d}{2})}^{2} = π \frac{d^{2}}{4}$ $r=d/2=> pir^2-> pi(d/2)^2 = pid^2/4$
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Given that $d = 20 f t$ $d=20 ft$ we have

$a = π \frac{20^{2}}{4}$ $a=pi(20^2)/4$

$a = 314.159 {feet}^{2}$ $a=314.159" feet"^2$ to 3 decimal places

Rounded to nearest foot $314 {feet}^{2}$ $314 " feet"^2$

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Question #04486

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