Question #607c0

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Question #607c0

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Answer 1 · 2016-05-02T09:43:50

1). $9 \times 10^{13} J$ $9xx10^13J$

Explanation:

To find out the required value we need to use the mass energy equivalence relation for energy $E$ $E$ ,

$E = m c^{2}$ $E=mc^2$
where $m$ $m$ is the mass and $c$ $c$ is the velocity of light in vacuum and is taken as $3 \times 10^{8} m s^{- 1}$ $3xx10^8ms^-1$ . Substituting the given numbers
$E = (1 \times 10^{- 3}) \times {(3 \times 10^{8})}^{2}$ $E=(1xx10^-3)xx(3xx10^8)^2$
or $E = 9 \times 10^{13} J$ $E=9xx10^13J$

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Question #607c0

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