In a $1 \cdot m g$ $1*mg$ mass of oxygen gas what is the number of $oxygen atoms$ $"oxygen atoms"$ ?

Question

In a $1 \cdot m g$ $1*mg$ mass of oxygen gas what is the number of $oxygen atoms$ $"oxygen atoms"$ ?

1 Answer

Impact of this question

1944 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-04T09:01:03

Approx, $4 \times 10^{19}$ $4xx10^19$ $individual oxygen atoms........$ $"individual oxygen atoms........"$

Explanation:

We calculate the quotient: $\frac{Mass}{Molar mass}$ $"Mass"/"Molar mass"$ , and get an answer in moles.

And thus $moles of dioxygen = \frac{1 \times 10^{- 3} \cdot g}{32.0 \cdot g \cdot m o l^{- 1}} = 3.1 \times 10^{- 5} \cdot m o l$ $"moles of dioxygen"=(1xx10^-3*g)/(32.0*g*mol^-1)=3.1xx10^-5*mol$ .

Now it is fact that $1 mole of stuff$ $"1 mole of stuff"$ contains, by definition, $Avogadro's number$ $"Avogadro's number"$ $=$ $=$ $6.022 \times 10^{23} \cdot m o l^{- 1}$ $6.022xx10^23*mol^-1$ .

And thus the $number of oxygen atoms = 2 \times 3.1 \times 10^{- 5} \cdot m o l \times 6.022 \times 10^{23} \cdot m o l^{- 1} = ? ?$ $"number of oxygen atoms"=2xx3.1xx10^-5*molxx6.022xx10^23*mol^-1=??$

Why did I include the $2$ $2$ in that product?

Science

Math

Humanities

... and beyond

In a $1 \cdot m g$ $1*mg$ mass of oxygen gas what is the number of $oxygen atoms$ $"oxygen atoms"$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

In a 1⋅mg1*mg mass of oxygen gas what is the number of oxygen atoms"oxygen atoms"?

1 Answer

Explanation:

Related questions

Impact of this question

In a $1 \cdot m g$ $1*mg$ mass of oxygen gas what is the number of $oxygen atoms$ $"oxygen atoms"$ ?