Question #6f7cd

1 Answer
Oct 3, 2017

The Rayleigh criterion for diffraction-limited vision for the minimum resolvable detail of objects located at a distance D, using a circular aperture (an iris) of diameter of d_e and light of wavelength lambda is given by the expression

sintheta_D=1.22lambda/theta_D

![http://www.studyadda](https://useruploads.socratic.org/8r8ltZ4S5axM0Pan6dtw_angle%20theta%20eye%20D%20a.GIF)

Inserting given values we get
sintheta=1.22xx(500xx10^-9)/(2.5xx10^-3)=2.44xx10^-4

We know that for very small value of sin theta

sintheta~~theta
=>theta~~2.44xx10^-4" radian"

a is the distance of separation of the objects being resolved. From the figure, for small angles

a=thetaxxD

Inserting calculated and given values we get

a=(2.44xx10^-4)xx(10xx10^3)=2.44" m"