What is the volume of "0.220 mols" of carbon monoxide gas found at STP?

1 Answer
Jun 3, 2016

If we assume that carbon monoxide ("CO") is an ideal gas, then we can use the ideal gas law:

\mathbf(PV = nRT)

where:

  • P is the pressure of the gas. We can use "bars" as our units.
  • V is the volume of the gas in "L".
  • n is the \mathbf("mol")s of gas.
  • R is the universal gas constant, "0.083145 L"cdot"bar/mol"cdot"K".
  • T is the temperature of the gas in "K".

At STP, T = 0^@ "C" = "273.15 K", and P = "1 bar". So, to get the volume, just solve for V.

color(blue)(V_"CO") = (nRT)/P

= ((0.220 cancel("mol CO"))("0.083145 L"cdotcancel("bar")"/"cancel("mol")cdotcancel("K"))(273.15 cancel("K")))/(1 cancel"bar")

= color(blue)("5.00 L") to 3 sig figs.